# Line slope calculator 4x+y=28

**Straight line given by points A[5; 8] and B[6; 4]**

## Calculation:

**Slope-intercept form of line:**y = -4x+28

**Canonical form of the line equation:**4x+y-28 = 0

**Parametric form of the line equation:**

x = t+5

y = -4t+8 ; t ∈ R

**Slope:**m = -4

**Slope angle of line: φ =**-75°57'50″ = -1.3258 rad

**X intercept:**x

_{0}= 7

**Y intercept:**y

_{0}= q = 28

**Distance line from the origin:**d

_{0}= 6.791

**The length of the segment AB: |AB| =**4.1231

**Vector: AB =**(1; -4)

**Normal vector: n =**(4; 1)

**Midpoint of the segment AB: M =**[5.5; 6]

**Perpendicular Bisector equation:**x-4y+18.5 = 0

**Vector OA = (5; 8) ; |OA| = 9.434**

**Vector OB = (6; 4) ; |OB| = 7.2111**

**Scalar product OA .OB = 62**

**Angle ∠ AOB = 24°18'16″ = 0.4242 rad**